5y^2+32y+12=0

Solution for 5y^2+32y+12=0 equation:

5y^2+32y+12=0

a = 5; b = 32; c = +12;
Δ = b2-4ac
Δ = 322-4·5·12
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-28}{2*5}=\frac{-60}{10}
=-6
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+28}{2*5}=\frac{-4}{10}
=-2/5
$